1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
|
// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART I : GENERATION
// CHAPTER 7: TARIFFS AND ECONOMIC ASPECTS IN POWER GENERATION
// EXAMPLE : 7.23 :
// Page number 83-84
clear ; clc ; close ; // Clear the work space and console
// Given data
cap_3sets = 600.0 // Capacity of 3 generators(kW)
no_3 = 3.0 // Number of sets of 600 kW
cap_4thset = 400.0 // Capacity of 4th generator set(kW)
no_4 = 1.0 // Number of sets of 400 kW
MD = 1600.0 // Maximum demand(kW)
LF = 0.45 // Load factor
cost_capital_kW = 1000.0 // Capital cost per kW installed capacity(Rs)
cost_annual_per = 0.15 // Annual cost = 15% of capital cost
cost_operation = 60000.0 // Annual operation cost(Rs)
cost_maintenance = 30000.0 // Annual maintenance cost(Rs)
fixed_maintenance = 1.0/3 // Fixed cost
variable_maintenance = 2.0/3 // Variable cost
cost_fuel_kg = 40.0/100 // Cost of fuel oil(Rs/kg)
cost_oil_kg = 1.25 // Cost of lubricating oil(Rs/kg)
calorific = 10000.0 // Calorific value of fuel(kcal/kg)
oil_consum = 1.0/400 // Consumption of lubricating oil. 1kg for every 400kWh generated
fuel_consum = 1.0/2 // Consumption of fuel. 1kg for every 2kWh generated
n_gen = 0.92 // Generator efficiency
heat_lost = 1.0/3 // Heat lost in the fuel to cooling water
theta = 11.0 // Difference of temperature between inlet and outlet(°C)
// Calculations
// Case(a)
rating_3set_A = cap_3sets/n_gen // Rating of first 3 sets(kW)
rating_4th_A = cap_4thset/n_gen // Rating of 4th set(kW)
// Case(b)
avg_demand_B = LF*MD // Average demand(kW)
hours_year = 365.0*24 // Total hours in a year
energy_B = avg_demand_B*hours_year // Annual energy produced(kWh)
// Case(c)
total_invest = (no_3*cap_3sets+cap_4thset*no_4)*cost_capital_kW // Total investment(Rs)
annual_cost = cost_annual_per*total_invest // Annual cost(Rs)
maintenance_cost = fixed_maintenance*cost_maintenance // Maintenance cost(Rs)
fixed_cost_total = annual_cost+maintenance_cost // Total fixed cost per annum(Rs)
fuel_consumption = energy_B*fuel_consum // Fuel consumption(Kg)
cost_fuel = fuel_consumption*cost_fuel_kg // Cost of fuel(Rs)
oil_consumption = energy_B*oil_consum // Lubrication oil consumption(Kg)
cost_oil = oil_consumption*cost_oil_kg // Cost of Lubrication oil(Rs)
var_maintenance_cost = variable_maintenance*cost_maintenance // Variable part of maintenance cost(Rs)
variable_cost_total = cost_fuel+cost_oil+var_maintenance_cost+cost_operation // Total variable cost per annum(Rs)
cost_total_D = fixed_cost_total+variable_cost_total // Total cost per annum(Rs)
cost_kWh_gen = cost_total_D/energy_B*100 // Cost per kWh generated(Paise)
// Case(c)
n_overall = energy_B*860/(fuel_consumption*calorific)*100 // Overall efficiency(%)
// Case(d)
weight_water_hr = heat_lost*fuel_consumption/(hours_year*theta)*calorific // Weight of cooling water required(kg/hr)
weight_water_min = weight_water_hr/60.0 // Weight of cooling water required(kg/min)
capacity_pump = weight_water_min*MD/avg_demand_B // Capacity of cooling water pump(kg/min)
// Results
disp("PART I - EXAMPLE : 7.23 : SOLUTION :-")
printf("\nCase(a): Rating of first 3 sets of diesel engine = %.f kW", rating_3set_A)
printf("\n Rating of 4th set of diesel engine = %.f kW", rating_4th_A)
printf("\nCase(b): Annual energy produced = %.1e kWh", energy_B)
printf("\nCase(c): Total fixed cost = Rs %.f ", fixed_cost_total)
printf("\n Total variable cost = Rs %.f ", variable_cost_total)
printf("\n Cost per kWh generated = %.f paise", cost_kWh_gen)
printf("\nCase(d): Overall efficiency of the diesel plant = %.1f percent", n_overall)
printf("\nCase(e): Quantity of cooling water required per round = %.2e kg/hr = %.f kg/min", weight_water_hr,weight_water_min)
printf("\n Capacity of cooling-water pumps under maximum load = %.f kg/min \n", capacity_pump)
printf("\nNOTE: Changes in obtained answer from that of textbook answer is due to more precision here')
|
