blob: b4ec99ef4bc9d7124d125a0a0d2d22fe351fe5a4 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
|
// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART IV : UTILIZATION AND TRACTION
// CHAPTER 6: MOTORS FOR ELECTRIC TRACTION
// EXAMPLE : 6.3 :
// Page number 790
clear ; clc ; close ; // Clear the work space and console
// Given data
V = 650.0 // Voltage supply(V)
r_A = 45.0 // Radius of driving wheel(cm)
r_B = 43.0 // Radius of driving wheel(cm)
N_A = 400.0 // Speed(rpm)
drop = 10.0 // Voltage drop(%)
// Calculations
rho = r_B/r_A
IR = drop*V/100 // Voltage drop(V)
V_A = (rho*(V-IR)+IR)/(1+rho) // Voltage(V)
V_B = V-V_A // Voltage(V)
N_A_A = N_A*(V_A-IR)/(V-IR) // N"_A(rpm)
N_B_B = N_A_A*r_A/r_B // N"_B(rpm)
// Results
disp("PART IV - EXAMPLE : 6.3 : SOLUTION :-")
printf("\nSpeed of first motor when connected in series, N_A = %.f rpm", N_A_A)
printf("\nSpeed of second motor when connected in series, N_B = %.f rpm\n", N_B_B)
printf("\nNOTE: Changes in the obtained answer from that of textbook is due to more precision here")
|