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// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART IV : UTILIZATION AND TRACTION
// CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS
// EXAMPLE : 1.24 :
// Page number 706
clear ; clc ; close ; // Clear the work space and console
// Given data
theta_f1 = 40.0 // Temperature rise(°C)
T = 100.0 // Heating time constant(min)
rated_2 = 2.0 // Motor at twice the continuously rating
// Calculations
loss_cu = 2.0**2 // Copper loss at twice full load in terms of W
loss_total = loss_cu+1 // Total losses at full load in terms of W
theta_f2 = theta_f1*loss_total/rated_2 // θ_f2(°C)
t = log(1-(theta_f1/theta_f2))*(-T) // Time for which motor can run at twice the continuously rated output without overheating(min)
// Results
disp("PART IV - EXAMPLE : 1.24 : SOLUTION :-")
printf("\nMotor can run at twice the continuously rated output without overheating for time, t = %.f min", t)
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