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// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART II : TRANSMISSION AND DISTRIBUTION
// CHAPTER 10: POWER SYSTEM STABILITY
// EXAMPLE : 10.18 :
// Page number 305
clear ; clc ; close ; // Clear the work space and console
// Given data
MVA = 210.0 // Rating of generator(MVA)
P = 2.0 // Number of poles
f = 50.0 // Frequency(Hz)
MI = 60.0*10**3 // Moment of inertia(kg-mt^2)
// Calculations
N = 120.0*f/P // Speed(r.p.m)
KE = 1.0/2*MI*(2*%pi*N/f)**2/10**6 // Energy stored in the rotor at rated speed(MJ)
H = KE/MVA // Inertia constant(MJ/MVA)
G = MVA
M = G*H/(180*f) // Angular momentum(MJ-sec/elect.degree)
// Results
disp("PART II - EXAMPLE : 10.18 : SOLUTION :-")
printf("\nEnergy stored in the rotor at the rated speed, KE = %.2e MJ", KE)
printf("\nValue of inertia constant, H = %.2f MJ/MVA", H)
printf("\nAngular momentum, M = %.3f MJ-sec/elect.degree", M)
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