blob: 8881564e67501e84900668577606379e9e5cb027 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
|
// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART II : TRANSMISSION AND DISTRIBUTION
// CHAPTER 10: POWER SYSTEM STABILITY
// EXAMPLE : 10.14 :
// Page number 304
clear ; clc ; close ; // Clear the work space and console
// Given data
Power = 20.0*10**3 // Rating of generator(kVA)
PF = 0.8 // Lagging power factor
fault = 0.5 // Reduction in output under fault
P = 4.0 // Number of poles
f = 50.0 // Frequency(Hz)
// Calculations
P_m = Power*PF // Output power before fault(kW)
P_e = fault*P_m // Output after fault(kW)
P_a = P_m-P_e // Accelerating power(kW)
w_s = 4.0*%pi*f/P // Speed
T_a = P_a*10**3/w_s // Accelerating torque at the time the fault occurs(N-m)
// Results
disp("PART II - EXAMPLE : 10.14 : SOLUTION :-")
printf("\nAccelerating torque at the time the fault occurs, T_a = %.2f N-m", T_a)
|