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// Exa 5.1
// To Calculate
// A) The system capacity if the cluster size, N (reuse factor), is 4 and
// B) The system capacity if the cluster size is 7.
// C) How many times would a cluster of size 4 have to be replicated to cover the entire cellular area?
// D) Does decreasing the reuse factor N increase the system capacity?
clc;
clear all;
ToCH=960;// Total available channels
Cellarea=6; //in km^2
Covarea=2000;//in km^2
N1=4; // Cluster Size
N2=7; //Cluster Size
//solution
Area1=N1*Cellarea;//for N=4
Area2=N2*Cellarea;//For N=7
No_of_clusters1=round(Covarea/Area1);
No_of_clusters2=round(Covarea/Area2);
No_of_CH1=ToCH/N1; // No of channels with cluster size 4
No_of_CH2=ToCH/N2; // No of channels with cluster size 7
SysCap1=No_of_clusters1*ToCH;
SysCap2=No_of_clusters2*ToCH;
printf(' System Capacity with cluster size 4 is %d channels \n ',SysCap1);
printf(' Number of clusters for covering total area with N equals 4 are %d \n ',No_of_clusters1);
printf(' System Capacity with cluster size 7 is %d channels \n',SysCap2);
disp(" It is evident when we decrease the value of N from 7 to 4, we increase the system capacity from 46080 to 79680 channels. Thus, decreasing the reuse factor (N) increases the system capacity.")
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