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//Section-14,Example-8,Page no.-PC.17
//To find Molecular formula of Hydrocarbon.
clc;
//(r(hydrocarbon)/r(CH_4))=(M(CH_4)/M(hydrocarbon))
M_CH4=16 //g/mol(molecular weight of CH4
r_hc=1 //rate of effusion of hydrocarbon
r_CH4=2 //rate of effusion of CH4
M_hc=(16/(1/2)^2)
disp(M_hc,'Molecular weight of hydrocarbon(g/mol)')
//The hydrocarbon formula may be (C_4H_10) which has a molecular weight of 58g/mol.
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