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//Example 5_17
clc();
clear;
//To find the lattice parameter and atomic diameter
lamda=0.171 //units in nm
theta=30 //units in degrees
d110=lamda/(2*sin(theta*%pi/180)) //units in nm
h=1
k=1
l=0
a=d110*sqrt(h^2+k^2+l^2) //units in nm
printf("The lattice parameter is a=%.3fnm",a)
//Assuming the metal is FCC
a1=0.171*sqrt(3) //units in nm
a2=0.148*sqrt(4) //units in nm
ad=a1/sqrt(2) //units in nm
printf("\n Atomic diameter is %.4fnm",ad)
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