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//Chapter 3, Exmaple 19, page 111
//Determine mean free path and ionization
clc
clear
//(a)Mean free path
//Based on equation 3.14 and 3.15
lambda = 1/(9003*0.5)
//(b)Ionization potential
Vi = 256584/9003
printf("\n lambda = %e m ",lambda)
printf("\n Vi = %f V ",Vi)
//answers may vary due to round off error
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