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//calculating hardness
//Example 1.1
clc
clear
//100gm of CaCO3 = 136gm of CaSO4
m=204//mass of the substance
wt=136//molecular mass
Eq=(m*100)/wt//Equivalents of CaCO3
printf('Thus Equivalents of CaCO3 = %3.2f mg/L or ppm',Eq)
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