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//developed in windows 8 operating system 64bit
//platform Scilab 5.4.1
//example 26_3w
clc;clear;
//Given Data
mass=1; //Mass of water (Unit: kg)
temp=100; //Temperature of water (Unit : degree centigrade)
density_water=1000; //Density of water (Unit: kg/m^3)
density_steam=0.6; //Density of steam (Unit : kg/m^3)
pressure=100*10^3; //Pressure of water(Unit : Pascal)
latent_heat_vapor=2.25*10^6; //Latent heat of vapourzation of water (Unit : Joules/kg)
//Calculation
volume_water=mass/density_water; //Calculation of volume of water (Unit: m^3)
volume_steam=mass/density_steam; //Calculation of volume of steam (Unit: m^3)
increased_volume=volume_steam-volume_water; //Calculation of change in volume (Unit; m^3)
work_done=pressure*increased_volume; //Calculation of work done (Unit: Joules)
change_internal_energy=latent_heat_vapor-work_done; //Calculation of change in internal energy (Unit: Joules)
disp(change_internal_energy,"The increase in internal energy of 1 kg water is (Unit:Joules)")
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