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clc
clear
//DATA GIVEN
IP=30; //indicted power in kW
BP=26; //Brake Power in kW
N=1000; //engine speed in R.P.M.
F=0.35; //fuel per brake power hour in kg/BP/h
C=43900; //calorific value of fuel used in kJ/kg
Fc=F*BP; //fuel consumption per hour
Mf=Fc/3600;
ETAti=IP/(Mf*C); //Indicted thermal eficiency
ETAtb=BP/(Mf*C); //Brake thermal efficiency
ETAm=BP/IP; //Mechanical efficiency
printf(' (i) The Indicted thermal eficiency is: %5.3f or %2.1f percent. \n',ETAti,(ETAti*100));
printf(' (ii) The Brake thermal efficiency is: %5.3f or %2.1f percent. \n',ETAtb,(ETAtb*100));
printf('(iii) Mechanical efficiency is: %5.3f or %2.1f percent. \n',ETAm,(ETAm*100));
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