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clc
clear
//DATA GIVEN
p=5; //pressure of steam in bar
Mwt=50; //mass of water in the tank in kg
t1=20; //initial temp. in deg. celsius
Ms=3; //amount of steam condensed in kg
t2=40; //final temp. in deg. celsius
We=1.5; //water equivalent of tank in kg
//At 5 bar, from steam tables
hf=640.1; //in kJ/kg
hfg=2107.4; //in kJ/kg
Mw=Mwt+We; //total mass of water in kg
//heat lost by steam = heat gained by water
//Ms[(hf+xhfg)-1*4.18*(t2-0)]=Mw[1*4.18*(t2-t1)]
x=[Mw*[1*4.18*(t2-t1)]/Ms+1*4.18*(t2-0)-hf]/hfg; //dryness fraction
printf('The Dryness fraction of steam, x is: %1.4f.',x);
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