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// Ex4_15
clc;
// Solution:
L1=(5.5-3.5);// Case 1
L2=2-0;// Case 2
L3=1.5-.5;// Case 3
ELML1=1+0+2;
ELML2=1+1+2;
ELML3=0+1+1;
printf("The order for Case 1 is %f and emission is type (%f) M2,Case 2 is %f and emission is type (%f) E2,Case 3 is %f and emission is type (%f) E1,Case 4 is not possible.",L1,ELML1,L2,ELML2,L3,ELML3)
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