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clc;
clear;
mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-16.4 Page No.361\n');
//Stopping rate
V=60*5280/3600;
Va=0.5*V;
D=400;
t=D/Va;
a=V/t;
mprintf('\n Stopping rate = %f ft/sec^2.',a);
//Stopping force
W=40000;
g=32.2;
F=W*a/g;
//Torque
r=36/2;
T=F*r;
mprintf('\n Torque = %f in-lb.',T);
//For each wheel
T=T/10;
//Braking normal force
rm=10;
f=0.4;
N=T/(f*rm);
mprintf('\n Braking normal force = %f lb.',N);
//Note-There is an error in the answer given in textbook
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