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clc;
clear;
mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-13.5 Page No.292\n');
//Normal circular pitch
Pc=0.524;
LA=4.77*%pi/180;
Pcn=Pc*cos(LA);
mprintf('\n Normal circular pitch = %f in.',Pcn);
//Force transmitted
hp=5;
n=29.2;
T=63000*hp/n;
Dp=10;
Ft=2*T/Dp;
mprintf('\n Force transmitted = %f lb.',Ft);
Vm=%pi*Dp*n/12;
//Dynamic load
Fd=(1200+Vm)*Ft/1200;
mprintf('\n Dynamic load = %f lb.',Fd);
//Force allowable
Su=95*10^3;
Y=0.392;
b=1;
Sn=0.5*Su;
Fs=Sn*Y*b*Pcn/%pi;
mprintf('\n Force allowable = %f lb.',Fs);
//Safty factor
Nsf=Fs/Fd;
mprintf('\n Safty factor = %f .',Nsf);
//Note-There is an error in the answer given in textbook
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