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//Tested on Windows 7 Ultimate 32-bit
//Chapter 8 Power Amplifiers Pg no. 279
clear;
clc;
//Given Data
//Figure 8.13
VCC=20;//collector supply voltage in volts
RC=270;//collector resistance in ohms
RE=150;//emitter resistance in ohms
R1=3.3D3;//divider network resistance R1 in ohms
R2=1.5D3;//divider network resistance R2 in ohms
VBE=0.7;//forward voltage drop of emitter diode in volts
B=100;//DC CE current gain beta
RL=470;//load resistance in ohms
C1=15D-6;//input coupling capacitance in farads
C2=15D-6;//output coupling capacitance in farads
//Solution
VB=VCC*R2/(R1+R2);//base to ground voltage in volts
VE=VB-VBE;//emitter to ground voltage in volts
IE=VE/RE;//emitter current in amperes
ICQ=IE;//neglecting base current, collector current is equal to emitter current in amperes
VC=VCC-ICQ*RC;//collector to ground voltage in volts
VCEQ=VC-VE;//collector to emitter quiscent voltage in volts
RL_dash=RC*RL/(RC+RL);//equivalent a.c. load resistance in ohms
VCEQ_midpt=(VCEQ+ICQ*RL_dash)/2;//collector to emitter voltage in Q point is set at midpoint of load line
Pout_max=0.5*VCEQ_midpt^2/RL_dash;//maximum output power for amplifier
printf("Maximum value of load power Pout(max) = %d milli-Watts",Pout_max*10^3);
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