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clc;clear;
//Example 9.7
//from 9.6
h2a=605.39;
h4a=880.36;
h3=1395.97;
Wnet=210.41;
//given data
n=0.80;
//calculations
// n = (h5 - h2a) / (h4a - h2a)
h5=(h4a - h2a)*n+h2a;
qin=h3-h5;
nth=Wnet/qin;
disp(nth,'thermal efficiency is')
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