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//Ex19_28 Pg-998
clc
disp("AB + A(B + C) + B(B + C) = AB + AB + AC + BB + BC")
//using distributive law
disp(" = AB + AC + B +BC ")
//using law 6
disp(" = AB + AC + B(1 + C) ")
//taking common B from B + BC
disp(" = AB + AC + B")
//using law 7
disp(" = B(A + 1) + AC")
//taking common B from AB + B
disp(" = B + AC")
//using law 7
disp("Therefore AB + A(B + C) + B(B + C) = B + AC")
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