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//Transport Processes and Seperation Process Principles
//Chapter 12
//Example 12.8-1
//Liquid Liquid and Fluid Solid Seperation Process
//given data
//for 80% extraction, unextracted fraction, Es=0.2
Es=0.2;
//Dab*(t/a*a) is constant
t1=3.11;//time reqd to leach 80% of solution
a2=1.5/2;//radius of reduced particale size
a1=2/2;//radius od the particle size
t2=(t1*a2*a2)/(a1*a1);
mprintf("the time of leaching= %f h",t2)