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clc;clear;
//Example 25.11
//calculation of sum of two octal numbers
//given values
X='256';//divident
Y='437';//divisor
//calculation
x=oct2dec(X);//decimal equivalent
y=oct2dec(Y);//decimal equivalent
z=x+y;
Z=dec2oct(z);//binary equivalent
disp(Z,'sum of the given octal numbers is')
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