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clear;
clc;
disp('Example 7.1');
// aim : To determine
// the specific enthalpy of water
// Given values
Tf = 273+100;// Temperature,[K]
// solution
// from steam table
cpl = 4.187;// [kJ/kg K]
// using equation [8]
sf = cpl*log(Tf/273.16);// [kJ/kg*K]
mprintf('\n The specific entropy of water is = %f kJ/kg K\n',sf);
// using steam table
sf = 1.307;// [kJ/kg K]
mprintf('\n From table The accurate value of sf in this case is = %f kJ/kg K\n',sf);
// There is small error in book's final value of sf
// End
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