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clear;
clc;
disp('Example 5.11');
// aim : To determine the
// (a) original and final volume of the gas
// (b) final pressure of the gas
// (c) final temperature of the gas
// Given values
m = .675;// mass of the gas,[kg]
P1 = 1.4;// original pressure,[MN/m^2]
T1 = 273+280;// original temperature,[K]
R = .287;//gas constant,[kJ/kg K]
// solution
// (a)
// using characteristic equation, P1*V1=m*R*T1
V1 = m*R*T1*10^-3/P1;// [m^3]
// also Given
V2 = 4*V1;// [m^3]
mprintf('\n (a) The original volume of the gas is = %f m^3\n',V1);
mprintf('\n and The final volume of the gas is = %f m^3\n',V2);
// (b)
// Given that gas is following the law P*V^1.3=constant
// hence process is polytropic with
n = 1.3; // polytropic index
P2 = P1*(V1/V2)^n;// formula for polytropic process,[MN/m^2]
mprintf('\n (b) The final pressure of the gas is = %f kN/m^2\n',P2*10^3);
// (c)
// since mass is constant so,using P*V/T=constant
// hence
T2 = P2*V2*T1/(P1*V1);// [K]
t2 = T2-273;// [C]
mprintf('\n (c) The final temperature of the gas is = %f C\n',t2);
// End
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