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clear;
clc;
disp('Example 1.7');
// Given values
m = 10; // mass of iron casting, [kg]
t1 = 200; // initial temperature, [C]
Q = -715.5; // [kJ], since heat is lost in this process
// From the table of average specific heat capacities
c = .50; // specific heat capacity of casting iron, [kJ/kg K]
// solution
// using heat equation
// Q = m*c*(t2-t1)
t2 = t1+Q/(m*c); // [C]
mprintf('\n The final temperature is t2 = %f C\n',t2);
// End
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