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clear;
clc;
disp('Example 1.10');
// Given values
m_dot = 3.045; // use of coal, [tonne/h]
c = 28; // calorific value of the coal, [MJ/kg]
P_out = 4.1; // output of turbine, [MW]
// solution
m_dot = m_dot*10^3/3600; // [kg/s]
P_in = m_dot*c; // power input by coal, [MW]
n = P_out/P_in; // thermal efficiency formula
mprintf('\n Thermal efficiency of the plant is = %f \n',n);
//End
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