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//Ex13_31 PG-13.17
clc
clear
printf("\n i)\n Conversion of binary number 101101.1101 to\n\n")
//conversion into decimal form
N=(1*2^5)+(0*2^4)+(1*2^3)+(1*2^2)+(0*2^1)+(1*2^0)+(1*2^(-1))+(1*2^(-2))+(0*2^(-3))+(1*2^(-4));
printf(" Decimal form = %.4f\n",N)
//Conversion into hexadecimal form
x=floor(N);//separating the integer part from the decimal part
b=dec2hex(x);
z=modulo(N,1);
d=0;
//converting the values after the decimal point into hexadecimal
//first we convert into decimal form and then into hexadecimal form
for i=2:5;//converting the values after the decimal point into hexadecimal
z=z*16;
q=floor(z);
d=d+q/(10^i);
if z>=1 then
z=z-q;
end
end
if (d==.10)
a=['A']
end
if (d==.11)
a=['B']
end
if (d==.12)
a=['C']
end
if (d==.13)
a=['D']
end
if (d==.14)
a=['E']
end
if (d==.15)
a=['F']
end
printf(" Hexadecimal form = %s.%s\n",b,a)
//conversion into octal form
z=modulo(N,1)
x=floor(N);//separating the decimal from the integer part
b=0;
c=0;
d=0;
while(x>0) //taking integer part into a matrix and convert to equivalent binary
y=modulo(x,8);
b=b+(10^c)*y;
x=x/8;
x=floor(x);
c=c+1;
end
for i=1:10;//converting the values after the decimal point intooctal
z=z*8;
q=floor(z);
d=d+q/(10^i);
if z>=1 then
z=z-q;
end
end
s=b+d;
printf(" octal form = %.2f\n\n",s);
printf("\n ii)\n Conversion of binary number 11011011.100101 to\n\n")
//conversion into decimal form
N=(1*2^7)+(1*2^6)+(0*2^5)+(1*2^4)+(1*2^3)+(0*2^2)+(1*2^1)+(1*2^0)+(1*2^(-1))+(0*2^(-2))+(0*2^(-3))+(1*2^(-4))+(0*2^(-5))+(1*2^(-6));
printf(" Decimal form =%.6f\n\n",N)
//Conversion into hexadecimal form
x=floor(N);//separating the integer part from the decimal part
b=dec2hex(x);
z=modulo(N,1);//first we convert into decimal form and then into hexadecimal form
d=0;
//converting the values after the decimal point into hexadecimal
for i=1:10;//converting the values after the decimal point into hexadecimal
z=z*16;
q=floor(z);
d=d+q/(10^i);
if z>=1 then
z=z-q;
end
end
printf(" Hexadecimal form\n integer part 11011011 = %s \n ",b)
printf("decimal part 100101 =%.2f\n\n",d)
//conversion into octal form
z=modulo(N,1)
x=floor(N);//separating the decimal from the integer part
b=0;
c=0;
d=0;
while(x>0) //taking integer part into a matrix and convert to equivalent binary
y=modulo(x,8);
b=b+(10^c)*y;
x=x/8;
x=floor(x);
c=c+1;
end
for i=1:10;//converting the values after the decimal point intooctal
z=z*8;
q=floor(z);
d=d+q/(10^i);
if z>=1 then
z=z-q;
end
end
s=b+d;
printf(" octal form =%.2f",s);
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