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// FUNDAMENTALS OF ELECTICAL MACHINES
// M.A.SALAM
// NAROSA PUBLISHING HOUSE
// SECOND EDITION
// Chapter 5 : DIRECT CURRENT MOTORS
// Example : 5.4
clc;clear; // clears the console and command history
// Given data
I = 40; // current in A
V_t = 230; // supply in V
N = 1100; // speed in rpm
R_a = 0.25; // armature resistance in Ω
R_sh = 230; //shunt resistance in Ω
// caclulations
I_sh = V_t/R_sh; // shunt field current in A
I_a = I - 1; // armature current in A
E_b = V_t - I_a*R_a; // back emf
T_a = 9.55*E_b*I_a/N; // amrature torque in N-m
// display the result
disp("Example 5.4 solution");
printf("\n The armature torque is \n T_a = %.2f N-m ",T_a );
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