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// FUNDAMENTALS OF ELECTICAL MACHINES
// M.A.SALAM
// NAROSA PUBLISHING HOUSE
// SECOND EDITION
// Chapter 3 : TRANSFORMER AND PER UNIT SYSTEM
// Example : 3.5
clc;clear; // clears the console and command history
// Given data
V_1 = 400 // primary voltage of transformer in V
V_2 = 100 // secondary voltage of transformer in V
I_0 = 0.4 // no-load current in A
I_2 = 100 // load draws current in A
cos_phi0 = 0.3 // power factor lagging from the supply
cos_phi2 = 0.6 // power factor lagging from the secondary
// caclulations
phi0 = acosd(0.3)
phi2 = acosd(0.6)
phi1 = phi0-phi2
a = V_1/V_2 // turn ratio
I_2! = I_2/a // secondary current equivalent to the primary
I_1 = sqrt((I_2!^2)+(I_0^2)+(2*I_2!*I_0*cosd(19.4))) // primary current in A
// display the result
disp("Example 3.5 solution");
printf(" \n Primary current \n I_1 = %.2f A \n", I_1);
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