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// FUNDAMENTALS OF ELECTICAL MACHINES
// M.A.SALAM
// NAROSA PUBLISHING HOUSE
// SECOND EDITION
// Chapter 3 : TRANSFORMER AND PER UNIT SYSTEM
// Example : 3.16
clc;clear; // clears the console and command history
// Given data
V_b = 220 // voltage in V
f = 50 // frequency in Hz
S_b = 600 // power ratings
R = 3 // resistance in ohm
X_L = 5 // inducatnce in ohm
Z = R+X_L // impedance
// caclulations
I_b = S_b/V_b // base value of current in A
Z_b = V_b^2/S_b // base value of impedance in ohm
R_pu = R/Z_b // per unit value of resistance in ohm
X_Lpu = X_L/Z_b // per unit value of impedance in ohm
Z_pu = abs(Z)/Z_b // per unit of value of impedance in ohm
Z_pu = R_pu+%i*X_Lpu // per unit of value of impedance in ohm NOTE:alternative method
// display the result
disp("Example 3.16 solution");
printf(" \n Per unit value of resistance \n R_pu = %.3f ohm \n", R_pu);
printf(" \n Per unit value of impedance \n X_Lpu = %.3f ohm \n", X_Lpu);
printf(" \n Per unit of value of impedance \n Z_pu = %.3f<%.f \n", abs(Z_pu),atand(imag(Z_pu),real(Z_pu)));
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