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// FUNDAMENTALS OF ELECTICAL MACHINES
// M.A.SALAM
// NAROSA PUBLISHING HOUSE
// SECOND EDITION
// Chapter 3 : TRANSFORMER AND PER UNIT SYSTEM
// Example : 3.14
clc;clear; // clears the console and command history
// Given data
E_1 = 500 // secondary induced voltages in V
E_2 = 450 // secondary induced voltages in V
kVA_1 = 100 // kVA ratings of transformer
kVA_2 = 200 // kVA ratings of transformer
Z_1 = 0.05 // impedance of transformer
Z_2 = 0.08 // impedance of transformer
// caclulations
Z1 =Z_1*E_1/(kVA_1*10^3/E_1) // actual impedance of 1st transformer in ohm
Z2 = Z_2*E_2/(kVA_1*10^3/E_2) // actual impedance of 2nd transformer in ohm
Z = %i*(Z1+Z2)
I_c = (E_1-E_2)/(Z) // value of the circulating current
// display the result
disp("Example 3.14 solution");
printf(" \n Value of the circulating current \n I_c = %.3f<%.f A \n", abs(I_c),atand(imag(I_c),real(I_c)));
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