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// FUNDAMENTALS OF ELECTICAL MACHINES
// M.A.SALAM
// NAROSA PUBLISHING HOUSE
// SECOND EDITION
// Chapter 2 : BESICS OF MAGNETIC CIRCUITS
// Example : 2.9
clc;clear; // clears the console and command history
// Given data
l = 0.45 // mean lenght in m
A = 25*10^-4 // cross sectional area in m^2
l_ag = 0.8*10^-3 // air gap in m
N = 500 // number of turns
I = 1.25 // current in A
fulx = 2.25*10^-3 // flux in Wb
phi = 1.5*10^-3 // flux in Wb
// caclulations
B = phi/A // magnetic flux density in Wb/m^2
MMF = N*I // magnetomotive force in At
H = B/(4*%pi*10^-7) // magnetomotizing force in At/m
MMF_ag = H*l_ag // magnetomotive force in At
MMF_i = MMF-MMF_ag // magnetomotive force for iron ring in At
H_i = MMF_i/l // magnetic field intensity for iron part in At/m
myu_r = B/((4*%pi*10^-7)*H_i) // relative permiability for iron
// display the result
disp("Example 2.9 solution");
printf(" \n Relative permiability for iron \n myu_r = %.2f \n", myu_r);
printf(" given current value in question is 2.25A, but in solution they took value of current as 1.25A ");
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