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// FUNDAMENTALS OF ELECTICAL MACHINES
// M.A.SALAM
// NAROSA PUBLISHING HOUSE
// SECOND EDITION
// Chapter 1 : REVIEW OF ELECRTIC CIRCUITS
// Example : 1.9
clc;clear; // clears the console and command history
// Given data
V_P = 340 // phase voltage in V
Z = 6+%i*8 // per phase impedance
// caclulations
V_AN = (V_P/exp(%i*(0)*(%pi/180))) // phase voltage
V_BN = (V_P/exp(%i*(-120)*(%pi/180))) // phase voltage
V_CN = (V_P/exp(%i*(120)*(%pi/180))) // phase voltage
I_Aa = V_AN/Z // line current for phase A in A
I_Bb = V_BN/Z // line current for phase B in A
I_Cc = V_CN/Z // line current for phase C in A
// display the result
disp("Example 1.9 solution");
printf(" \n Line currents are \n I_Aa = %.2f<%.2f A \n", abs(I_Aa),atand(imag(I_Aa),real(I_Aa)) );
printf(" I_Bb = %.2f<% 2f A \n", abs(I_Bb),atand(imag(I_Bb),real(I_Bb)) );
printf(" I_Cc = %.2f<% 2f A \n", abs(I_Cc),atand(imag(I_Cc),real(I_Cc)) );
printf(" \n The load is balanced, so the value of the neutral current will be zero")
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