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//Eg-9.7
//pg-403
clc
clear
p=6.5;
n = 6;
a = 0.5;
prodd=1;
for i = 1:n
prodd = prodd*(p-i);
end
req=prodd*(22/7)^.5
disp("required value")
disp(req)
printf('\n\n The minor difference in the answer is because of using the value of 22/7 in the place of pi\n')
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