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//Eg-13.14
//pg-556
clear
clc
deff('out = func(in1,in2)','out = -0.3*(in2-50)^1.25')
h = 0.1;
x(1) = 0;
y(1) = 100;
y(2) = 96.20249; //from the question
x(2) = x(1) + h;
n = 10/h;
for(i = 1:n)
x(i+1) = x(i) + h ;
end
for(i = 2:n)
yb(i+1) = y(i-1) + 2*h*func(x(i),y(i));
y(i+1) = y(i) + h/2*(func(x(i),y(i)) + func(x(i+1),yb(i+1)));
end
printf(' x y\n')
for(i = 1:10)
printf('%f %f\n',x(i*10+1),y(i*10+1))
end
printf('\n\nThe value of T at t = 10 agrees with that of the analytical solution:\nT = 50 + (0.075t + 0.37604)^-4\n')
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