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//Eg-13.12
//pg-552
clear
clc
y(1) = 1;
h = 1;
printf('For h = 1\n')
printf(' x y\n')
for(i = 1:3)
x(i) = i; //since h = 1
y(i+1) = y(i)/(1+2*h);
printf(' %f %f\n',x(i),y(i+1))
end
h = 0.5;
printf('\nFor h = 0.5\n')
printf(' x y\n')
n = (3.0-0.5)/0.5+1;
for(i = 1:n)
x(i) = 0.5 + (i-1)*h; //since h = 0.5
y(i+1) = y(i)/(1+2*h);
printf(' %f %f\n',x(i),y(i+1))
end
printf('Observe that the implicit method is stable for h = 1, whereas the explicit method is not.')
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