blob: ee69c21d49d40a139f1ef83d1bf54904adcaed4d (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
|
clc
//initialisation of variables
d1=0.67//ft
h1=2.00//ft
h2=4.04//ft
hv1=0.062//ft
hv2=0.254//ft
d=0.19//ft
h=0.2//ft
h1=0.04//ft
q=0.644//ft
q1=0.65//ft
v=0.92//ft
d2=6.5//ft
v1=3.69//ft
d3=0.542//ft
hv3=0.21//ft
delv=0.15//ft
d4=0.02//ft
//CALCULATIONS
H=d1+hv1//ft
H1=d1+hv2//ft
he=h*d//ft
hi=d+h1//ft
H2=d3+hv3//ft
he1=h*delv//ft
S=d4+h1//ft
//RESULTS
printf('the required slope=% f ft',hi)
printf('the lower sewer and the invert drop in the transition=% f ft',S)
|
