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//Chapter-5,Example 15,Page 128
clc();
close();
K1=2.45*10^-5 //rate constant at 273 K
K2=162*10^-5 //rate constant at 303 K
T1=273 //temperature in Kelvin
T2=303 //temperature in Kelvin
R=1.987 //gas constant
Ea= log10(K2/K1)*2.303*R*T1*T2/(T2-T1)
printf('the activation energy is Ea = %.f cal/mole' ,Ea)
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