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//Chapter-5,Example 10,Page 125
clc();
close();
T1=50 //time in sec
T2 = 25 //time in sec
a1=0.5 //initial concentration
a2= 1
// (T1/T2) = (a2/a1)^(n-1)
//therefore (50/25) =(1/0.5)^(n-1)
// 2=2^(n-1)
// n=2
//hence its 2nd order
t_half= T1
k=1/(a1*t_half)
//assume y= a-x
y=0.2*a1 //remaining concentration
t=(a1-y)/(a1*k*(y))
printf('the time taken is %.f sec ',t)
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