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//Chapter-4,Example 16,Page 97
clc;
close;
//since the operation is isothermal & hte gas is ideal therefore..
delta_E= 0 // from 1st law of thermodynamics
P= 1 //pressure in atm
V1= 10 // volume in cubic decimeter
V2= 20 // volume in cubic decimeter
W= P*(V2-V1)*(8.314/0.0821) // work done by system
q=W //from 1st law of thermodynamics
delta_H = delta_E + W
printf(' q = %.2f J',q)
printf('\n W = %.2f',W)
printf('\n delta_E = %.f J',delta_E)
printf('\n delta_H = %.2f J',delta_H)
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