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//Chapter-3,Example 4,Page 57
clc;
close;
m=234 // atomic mass of uranium
M_0 = 4 // initial mass of uranium
t_half= 2.48*10^5 // half life of uranium
t= 62000*365*24*3600 // time period
lamda=8.88*10^-14
M= M_0*exp(-lamda*t)
printf('Mass of uranium left unchanged is %.3f mg', M)
N= (M*6.023*10^20)/m
A= lamda*N
printf(' \n activity of uranium is %.3f disintigrations/sec ', A)
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