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//Chapter-3,Example 17,Page 61
clc;
close;
m_Ca = 39.975 //atomic mass of Calcium in a.m.u.
a_no= 20 //atomic number of calcium
m_proton = 1.0078 //mass of proton
m_neutron = 1.0086 //mass of neutron\
delta_m=a_no*(m_neutron + m_proton)- m_Ca //mass defect
energy= delta_m*931/40 //binding energy per nucleon
printf('binding energy per nucleon is %.3f MeV',energy)
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