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//===========================================================================
// chapter 6 example 17
clc;
clear;
//input data
C = 0.03*10^-6; //capacitance in F
d = 0.001; //thickness in m
er = 2.6; //dielectric constant
e0 = 8.85*10^-12; //dielectric strength
E0 = 1.8*10^7
//formula
//C=e0*er*A/d
//e0=v/d
//calculation
A = (C*d)/(e0*er); //area of dielectric needed in m^2
Vb = E0*d; //breakdown voltage in m
//result
mprintf('area=%3.2f.m^2\n',A);
mprintf(' breakdown voltage=%3.1e.V\n',Vb);
//===========================================================================
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