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//==============================================================================
// chapter 6 example 15
clc;
clear;
//input data
n = 12; //number of plates
er = 4; //relative permitivty
d = 1.0*10^-3; //distance between plates in m
A = 120*150*10^-6; //area in m^2
e0 = 8.854*10^-12; // in F/m
//calculation
c = (n-1)*e0*er*A/d; //capacitance in F
//result
mprintf('capacitance=%3.4e.F\n',c);
//==============================================================================
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