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//scilab 5.4.1
clear;
clc;
printf("\t\t\tProblem Number 7.8\n\n\n");
// Chapter 7 : Mixtures Of Ideal Gases
// Problem 7.8 (page no. 329)
// Solution
//We will take as a basis 100 lbm of mixture.
//Dividing colomn 2 by 3 gives us mass/molecular weight or moles of each constituents.The total number of moles in the mixture is the sum of coloumn 4,and the molecular weight of the mixture is the mass of the mixture(100 lbm) divided by the number of moles
//In coloumn 5,mole fraction is given by moles/total mole
printf("Basis:100 pounds of gas mixture\n\n")
printf("gas Mass Molecular Moles Mole Percent \n")
printf(" lbm weight MW fraction Volume \n")
printf("O2 23.18 32.00 0.724 %f %f \n",(0.724/3.45),(0.724/3.45)*100)
printf("N2 75.47 28.02 2.693 %f %f \n",(2.692/3.45),(2.692/3.45)*100)
printf("A 1.30 39.90 0.033 %f %f \n",(0.033/3.45),(0.033/3.45)*100)
printf("CO2 0.05 44.00 - - - \n")
printf(" =100.00 =3.45 =1.00 = 100 \n ")
printf(" MWm=100/3.45=28.99 ")
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