blob: 639d3aa224b1820adc4391920cf8bf3fad5e9937 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
|
//scilab 5.4.1
clear;
clc;
printf("\t\t\tProblem Number 4.11\n\n\n");
// Chapter 4 : The Second Law Of Thermodynamics
// Problem 4.11 (page no. 159)
// Solution
//Let is assume that a Carnot engine cycle operates between two temperatures in each case.
t=1000; //(unit:fahrenheit)
//converting temperatures to absolute temperatures;
T1=t+460;
//T1*deltaS=Qin;
Qin=100; //Unit:Btu //heat added to the cycle
deltaS=Qin/T1; //Change in entropy //Btu/R
T2=50+460; //converting 50 F temperature to absolute temperature;
Qr=T2*deltaS; //Heat rejected //Unit:Btu
printf("%f Btu energy is unavailable with respect to a receiver at 50 fahrenheit \n",Qr);
T2=0+460; //converting 0 F temperature to absolute temperature;
Qr=T2*deltaS; //Heat rejected //unit:Btu
printf("%f Btu energy is unavailable with respect to a receiver at 0 fahrenheit \n",Qr);
|
