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clc
clear
Ma=35500; //kg of steam
Mf=3460;
CV=39500;
Ms=Ma/Mf;
Hfw2=313.9; //in kJ/kg
Hfw1=71.4; //in kJ/kg
Q=Ma*(Hfw2-Hfw1); //Heat added in economizer
H=2915.0; //in kJ/kg
Me=(Ms*(H-Hfw2))/2257;
printf('Equivalent evaporation: %3.2f kg/kg of Oil',Me);
printf('\n');
Eff1=(Ma*100*(H-Hfw2))/(Mf*CV);
printf('Thermal Efficiency of boiler: %3.1f Percent',Eff1);
printf('\n');
Eff2=(Ma*100*(H-Hfw1))/(Mf*CV);
printf('Thermal Efficiency of Boiler plant: %3.1f Percent',Eff2);
printf('\n');
HU=860875000/(Mf*CV);
printf('Heat Utilized by Economizer: %3.1f Percent',HU);
printf('\n');
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