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clc
clear
Ma=1800; //kg/hr
P=12; //in bar
x=0.97; //Dryness Fraction
Tfw=105; //in C
Mf=2050; //in kg/hr
CV=27400; //in kJ/kg
Q=Mf*CV;
printf('Heat Supplied: %3.2f kJ',Q);
printf('\n');
//At 12 bar pressure
Hf=798.6; //in kJ/kg
Hfg=1986.2; //in kJ/kg
H=Hf+(x*Hfg);
Hfw=4.187*Tfw;
Me=(Ma*(H-Hfw))/(2257*Mf);
printf('Equivalent Evaporation: %3.2f kg/kg of coal',Me);
printf('\n');
Eff=(Ma*100*(H-Hfw))/(CV*Mf);
printf('Efficiency of boiler: %3.2f Percent',Eff);
printf('\n');
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