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clc
clear
Ms=7.3; //kg/kg of fuel
Tfw=46; //in C
P=10; //in bar
FOE=1.17; //Factor of Evaporation
Eff=0.79;
Me=FOE*Ms;
printf('Equivalent Evaporation: %3.2f kg/kg of coal',Me);
printf('\n');
Hfw=192.6; //in kJ/kg
Hg=2778.1; //in kJ/kg
Tsat=179.9; //in C
Cps=2.1; //in kJ/kg K
H=(2257*FOE)+Hfw;
Tsup=((H-Hg)/Cps)+Tsat;
printf('Temperature of Superheated Steam: %3.1f C',Tsup);
printf('\n');
CV=(Ms*(H-Hfw))/Eff;
printf('Calorific Value: %3.1f kJ/kg',CV);
printf('\n');
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