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clc
clear
Ma=1100; //in kg/hr
CV=33000; //in kJ/kg
Tfw=46; //in C
P=10; //in bar
x=0.9; //Dryness Fraction
Eff=0.81; //Efficiency
Hf=762.8;
Hfg=2015.3;
H=Hf+(x*Hfg);
Hfw=192.6;
Mf=(Ma*(H-Hfw))/(CV*Eff);
printf('Amount of Coal Consumed per hour: %3.1f kg',Mf);
printf('\n');
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