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clc
clear
Mf=1300; //in kg
Ma=13000; //in kg
P=7; //in bar
Cpw=4.187; //in kJ/kg K
CV=30000; //in kJ/kg
x=0.95; //Dryness Fraction
Tfw=40; //in C
Hfw=Tfw*Cpw;
//At 7 bar
Hf=697.2; //in kJ/kg
Hfg=2066.3; //in kJ/kg
H=Hf+(x*Hfg);
Ms=Ma/Mf;
Me=(Ms*(H-Hfw))/(2257);
printf('Equivalent evaporation: %3.2f kg/kg of coal',Me);
printf('\n');
Eff=100*(Ma*(H-Hfw))/(Mf*CV);
printf('Boiler Efficiency: %3.1f Percent',Eff);
printf('\n');
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